What is the resistance of a circuit producing 2 Amperes of current at a driving voltage of 1.6 Volts?

What is the resistance of a circuit producing 2 Amperes of current at a driving voltage of 1.6 Volts?

• A. 1.8 Ohms
• B. 2.8 Ohms
• C. 0.8 Ohms
• D. 9 Ohms

Answer: (C)

To find the resistance of a circuit when the current and voltage are known, Ohm's Law is used, which is expressed as: \[ R = \frac{V}{I} \] where \( R \) is the resistance, \( V \) is the voltage, and \( I \) is the current. In this case, the voltage \( V \) is 1.6 Volts, and the current \( I \) is 2 Amperes. When we apply these values: \[ R = \frac{1.6\ \text{V}}{2\ \text{A}} = 0.8\ \text{Ohms} \] This calculation shows that the resistance is 0.8 Ohms, making this the correct answer for the question. Understanding how to apply Ohm's Law correctly is key in circuit analysis, particularly when one needs to determine how components will behave under certain electrical conditions.

To find the resistance of a circuit when the current and voltage are known, Ohm's Law is used, which is expressed as:

[ R = \frac{V}{I} ]

where ( R ) is the resistance, ( V ) is the voltage, and ( I ) is the current.

In this case, the voltage ( V ) is 1.6 Volts, and the current ( I ) is 2 Amperes. When we apply these values:

[ R = \frac{1.6\ \text{V}}{2\ \text{A}} = 0.8\ \text{Ohms} ]

This calculation shows that the resistance is 0.8 Ohms, making this the correct answer for the question.

Understanding how to apply Ohm's Law correctly is key in circuit analysis, particularly when one needs to determine how components will behave under certain electrical conditions.